Great project — and a smart instinct to check how the thruster behaves *once the hull is moving*, because that's where most back-of-envelope propulsion plans go wrong. Here's the short version of what I found, followed by a complete HTML page you can drop into your site. **Headline results (best estimates, anchored to the Shinmaywa rating):** | MPH | Thrust | kW | |-----|--------|-----| | 0 | 3,200 N (720 lbf) | 3.20 | | 0.5 | ~2,720 N (610 lbf) | ~2.89 | | 1.0 | ~2,250 N (505 lbf) | ~2.58 | | 1.5 | ~1,770 N (400 lbf) | ~2.27 | Key physics: thrust falls roughly **linearly** with speed (blades see reduced angle of attack), hitting zero around **~3.4 mph**. Power draw falls much more slowly (blade profile drag keeps absorbing torque), so **don't size your solar array below ~3.2 kW per unit** if you want full thrust on demand. Against my estimate of your hull's drag (~21 m² effective drag area from the four angled columns + cables), one unit gives a calm-water top speed of **~1.0 mph**, two units **~1.3 mph**. All figures ±25–30% until you calibrate with a dockside bollard test. Here's the full HTML page: ```html
Shinmaywa-type submersible mixer (2.5 m propeller, 3,200 N / 720 lbf bollard thrust, 2–3.2 kW) repurposed as a low-speed thruster — estimated thrust and electrical power draw vs vessel speed.
| Vessel speed (mph) | (m/s) | Thrust (N) | Thrust (lbf) | Power draw (kW) | Propulsion efficiency* |
|---|---|---|---|---|---|
| 0 (stationary) | 0 | 3,200 | 720 | 3.20 | — (bollard) |
| 0.5 | 0.22 | 2,720 | 610 | 2.89 | 21% |
| 1.0 | 0.45 | 2,250 | 505 | 2.58 | 39% |
| 1.5 | 0.67 | 1,770 | 400 | 2.27 | 52% |
| 2.0 (extrapolated) | 0.89 | 1,290 | 290 | 1.96 | 59% |
*Efficiency = thrust × speed ÷ electrical power. It rises with speed (the rotor unloads), but absolute thrust margin shrinks. Thrust reaches zero at ≈3.4 mph; power draw never reaches zero (≈1.1 kW remaining at that point, absorbed by blade profile drag). Running two units simply doubles both columns.
| Speed (mph) | Optimistic thrust (N) | Best-estimate thrust (N) | Conservative thrust (N) | Power draw range (kW) |
|---|---|---|---|---|
| 0 | 3,200 | 3,200 | 3,200 | 3.20 |
| 0.5 | 2,960 | 2,720 | 2,550 | 2.85 – 3.20 |
| 1.0 | 2,730 | 2,250 | 1,900 | 2.49 – 3.20 |
| 1.5 | 2,500 | 1,770 | 1,250 | 2.14 – 3.20 |
Momentum theory gives two exact identities for a rotor in stationary water:
power P = T × vᵢ (where vᵢ is the induced velocity at the rotor plane),
and the far slipstream moves at w = 2·vᵢ. With the rated 3,200 W and 3,200 N:
vᵢ = 3200/3200 = 1.0 m/sw ≈ 2.0 m/sAₑ = T³/(2ρP²) ≈ 1.56 m² (D ≈ 1.41 m)The physical propeller is 2.5 m (disk area 4.91 m²), so the unit performs like an ideal actuator about 1.4 m across — a figure of merit of ≈0.68 versus a perfect 2.5 m disk (which would give ≈4,700 N at this power). That is entirely typical for real thruster hardware, so the published rating looks credible and is used here at face value.
At fixed shaft speed and fixed pitch, thrust vanishes when the advance speed reaches the blades'
zero-lift pitch speed. For heavily loaded, low-pitch mixers this occurs at roughly
0.6–0.8× the bollard slipstream speed, i.e. Vₔₜ ≈ 1.2–1.6 m/s.
Adopted central value: 1.5 m/s ≈ 3.4 mph.
Intuition: as the seastead moves forward, water already flows through the rotor, reducing each blade's
angle of attack — like a fan on a moving cart. Torque (and therefore electrical power) decays more
slowly than thrust because blade profile drag keeps absorbing torque even after net thrust reaches zero.
This mirrors standard propeller Kₜ/K₌ chart behavior (e.g., Wageningen B-series).
Optimistic bound (only reachable if the drive held power constant): the constant-power actuator-disk equation, solved for T at each speed:
T³ + 2ρAₑ·P·V·T − 2ρAₑ·P² = 0, ρ = 1025 kg/m³Conservative bound: effective zero-thrust speed lowered to 1.1 m/s (shorter pitch / shroud drag), power factor 0.545.
Based on your description — four 4-ft-wide columns, 13 ft long at 45° (vertical extent ≈9.2 ft each ≈ 147 ft² frontal) plus cable/appendage allowance ≈ 175 ft² (16.3 m²), at Cₖ ≈ 1.3 ⇒ drag area CₖA ≈ 21 m². Drag = ½ρU²·CₖA ≈ 10,760×U² (N):
| Speed | Drag (N) | Drag (lbf) |
|---|---|---|
| 0.5 mph | 540 | 120 |
| 1.0 mph | 2,150 | 480 |
| 1.5 mph | 4,840 | 1,090 |
Solving thrust = drag against the best-estimate thrust curve: ≈1.0 mph with one unit (range 0.9–1.2 across scenarios), ≈1.3 mph with two units (range 1.2–1.6). If your columns are round rather than square, drag drops ~30–40% and speeds rise accordingly — send me the real cross-section and cable layout and I'll tighten this.
T = T₀ − kV lets you refit everything with two numbers.