Approximate Side-Load Strength of One Leg
Important: This is only a rough first-pass estimate, not a structural certification.
A real design like this needs a naval architect and a marine structural engineer.
Wave slam, fatigue, weld details, buckling, stress concentrations at attachments, corrosion, and dynamic resonance can all reduce safe load a lot.
1) What I assumed from your description
For each main leg/float:
- Length: 19 ft
- About half submerged, so submerged depth: 9.5 ft
- Foil chord: 10 ft
- Thickness / width: 3 ft
- Shell material: marine aluminum
- Shell thickness: 1/2 inch = 0.0417 ft
I interpreted your question as:
- The wave pushes sideways on a leg
- The force is treated as an evenly distributed load along the submerged portion
- The leg behaves roughly like a cantilever fixed at the deck/frame connection
- We want the approximate total sideways force that would make the aluminum shell reach failure/begin to yield
Big uncertainty: The actual strength depends hugely on the internal structure.
A 1/2-inch aluminum skin alone is very different from a leg with internal webs, frames, bulkheads, and a strong root attachment.
In practice, the connection to the main triangle structure is likely the most critical part.
2) Simplified structural model
To get an estimate, I modeled the leg as a hollow rectangular section approximately:
- Fore-aft depth: 10 ft
- Sideways width: 3 ft
- Wall thickness: 0.5 in
For sideways loading, the leg bends in the fore-aft direction, so the important section modulus is based mainly on the 10 ft chord depth.
Using a thin-wall rectangular approximation:
- Outer dimensions:
b = 3 ft, h = 10 ft
- Thickness:
t = 0.0417 ft
- Approximate section modulus: S ≈ 1.17 ft³
Typical marine aluminum yield strength varies by alloy and weld condition. A rough range:
- 20,000 psi = conservative welded-region estimate
- 30,000 psi = stronger alloy / less weld weakening estimate
Converting section modulus to cubic inches:
1.17 ft³ × 1728 = 2020 in³
Estimated yield bending moment:
- Conservative:
M ≈ 20,000 × 2020 = 40,400,000 in-lb
- Higher estimate:
M ≈ 30,000 × 2020 = 60,600,000 in-lb
Convert to ft-lb:
- Conservative:
≈ 3.37 million ft-lb
- Higher estimate:
≈ 5.05 million ft-lb
3) Distributed sideways load that causes that moment
If the submerged length is L = 9.5 ft and load is uniform, then for a cantilever:
M = wL²/2
So:
w = 2M / L²
With L² = 90.25:
- Conservative load per foot:
w ≈ 74,700 lb/ft
- Higher estimate load per foot:
w ≈ 111,900 lb/ft
Total distributed force on one leg:
F = wL
- Conservative total force:
≈ 710,000 lb
- Higher estimate total force:
≈ 1,060,000 lb
Rough answer for one leg:
If treated as a simple hollow aluminum box with 1/2-inch skin, the shell-only bending estimate says
on the order of 0.7 to 1.1 million pounds of evenly distributed sideways load on the submerged 9.5 ft
would be needed to drive the section toward yielding.
4) But real failure may happen much earlier
The numbers above are not a safe working load. Real failure can happen much sooner because of:
- Buckling of the 1/2-inch plating
- Weld softening in heat-affected zones
- Stress concentration where the leg joins the platform
- Local denting or panel instability
- Dynamic slam loads from steep waves
- Fatigue cracking from repeated cycling
- Twisting, not just pure bending
A practical first-pass allowable load might need to be only around 1/4 to 1/6 of that yield estimate unless the leg has substantial internal stiffening.
That would suggest a more cautious “don’t even get near this” range of roughly:
- 120,000 to 280,000 lb total sideways load per leg
And even that is still a very rough conceptual estimate.
5) What wave height might cause that much side force?
This part is much more uncertain than the structural estimate.
For a side force on the submerged portion of one leg, a crude hydrodynamic estimate is:
F = 0.5 ρ Cd A V²
Where:
ρ = seawater density ≈ 1025 kg/m³
Cd = side-force coefficient, maybe 1.0 to 2.0 depending on angle and unsteady flow
A = projected side area of submerged part ≈ 9.5 ft × 19 ft? or more conservatively the actual submerged side area of the leg body
Because your geometry is unusual, I used a practical projected side area of about:
A ≈ 9.5 ft × 10 ft = 95 ft² = 8.8 m²
Then solving for water particle velocity needed for various loads:
| Total side force on one leg |
Approx. water velocity needed |
Comment |
| 100,000 lb |
~10 to 14 m/s |
Very severe, extreme breaking-wave type flow |
| 250,000 lb |
~16 to 23 m/s |
Exceptionally violent slam / breaking crest event |
| 700,000 lb |
~27 to 39 m/s |
Implausibly high for ordinary wave orbital flow; more like impact/slam territory |
Those velocities are enormous. That suggests:
- Ordinary non-breaking waves probably do not create the million-pound distributed side load on one leg.
- Breaking waves, slamming, and snap-roll events are the real danger.
Very rough wave-height interpretation
There is no single clean conversion from wave height to side force because it depends on:
- wave period
- whether the wave is breaking
- platform natural roll period
- wave direction relative to the platform
- how much the seastead is already heeled
- whether one leg emerges and re-enters
But as a rough conceptual guide:
| Wave condition |
Likely implication |
| 3 to 6 ft beam waves |
Usually far below shell-yield loads, but may cause uncomfortable motion |
| 8 to 12 ft steep beam seas |
Could produce significant cyclic loads, especially if periods match roll response |
| 15 to 25+ ft breaking beam seas |
Now you may get severe impact/slam loads and dangerous dynamic events |
Bottom line on wave height:
A simple static estimate suggests that ordinary waves are unlikely to directly bend a leg to shell yield.
The more realistic threat is large steep or breaking side waves, likely in the 15+ ft range, especially if they cause impact, rapid roll, or repeated fatigue loading.
6) Final answer
Using a very simplified cantilever model for one leg made from 1/2-inch marine aluminum with approximate section 10 ft × 3 ft:
- Estimated shell-yield distributed side force: about 700,000 to 1,060,000 lb total on one leg
- Equivalent uniform load: about 75,000 to 112,000 lb/ft over the submerged 9.5 ft
But for design purposes, real-world allowable load may be much lower, possibly more like:
- 120,000 to 280,000 lb per leg until a real structural analysis is done
As for wave height:
- Normal moderate waves likely won’t reach those loads
- Large steep or breaking beam waves are the concern
- A dangerous regime may begin somewhere around 15 to 25 ft beam seas, depending heavily on period and whether waves break/slam
7) Strong recommendation
Before building this, you should get:
- Global stability analysis
- Motion response / roll period analysis
- Finite element analysis of each leg root and weldment
- Buckling analysis of the 1/2-inch shell panels
- Slamming / breaking-wave load assessment
If you want, I can next produce an improved engineering estimate using a more realistic model with:
- exact leg orientation,
- internal bulkheads/stiffeners,
- leg spacing,
- platform displacement, and
- roll angle under beam waves.
Prepared as a conceptual estimate only.