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Full‑scale leg diameter = 4 ft = 48 in. Model leg diameter = 5 in.
Scale factor (full : model) = 48 in / 5 in = 9.6 : 1.
Thus the model is 1⁄9.6 ≈ 10.4 % of the full‑scale size in every linear dimension.
| Parameter | Full Scale | Model (scaled) |
|---|---|---|
| Diameter | 48 in (4 ft) | 5 in (by design) |
| Length | 35 ft = 420 in | 420 in ÷ 9.6 = 43.75 in (≈ 44 in) |
| Vertical drop (45° incline) | 35 ft × sin 45° = 24.75 ft = 297 in | 297 in ÷ 9.6 = 30.9 in |
| Horizontal offset (45° incline) | 35 ft × cos 45° = 24.75 ft = 297 in | 297 in ÷ 9.6 = 30.9 in |
| Submerged length (≈ 60 % underwater) | 0.60 × 420 in = 252 in | 0.60 × 43.75 in = 26.25 in |
Full‑scale body: 60 ft × 14 ft × 8 ft → 720 in × 168 in × 96 in.
Typical 55‑gal plastic drum: 22.5 in OD, 33.5 in height (empty).
| Dimension | Model (with barrels) | Full‑scale equivalent (×9.6) |
|---|---|---|
| Length (along the hull) | 67 in (≈ 5 ft 7 in) | 67 in × 9.6 = 643 in = 53.6 ft |
| Width / Diameter | 22.5 in (≈ 1 ft 10 in) | 22.5 in × 9.6 = 216 in = 18 ft |
| Height (if placed on side) | 33.5 in (≈ 2 ft 9 in) | 33.5 in × 9.6 = 322 in = 26.8 ft |
Note: The barrel‑derived full‑scale length (≈ 53.6 ft) is close to the target 60 ft; the width (18 ft) is larger than the original 14 ft. This is acceptable for a first‑order model.
When the same material is used in model and full scale, weight scales with volume (i.e. with the cube of the linear scale factor).
| Item | Full‑scale weight (steel*) | Model weight (steel*) |
|---|---|---|
| One leg (solid cylinder) | π × (24 in)² × 420 in × 0.2836 lb/in³ ≈ 215 600 lb | 215 600 lb ÷ 884.7 ≈ 244 lb |
| All 4 legs | ≈ 862 400 lb | ≈ 976 lb |
*Using steel density 0.2836 lb/in³ (≈ 490 lb/ft³). In practice you will probably build the model legs from a lightweight material (e.g., PVC, foam, or wood), so the actual model weight will be far lower.
| Item | Full‑scale weight (steel hull) | Model weight (plastic barrels) |
|---|---|---|
| Hull (sheet‑metal box) | ≈ 58 500 lb (see calculation below) | Two 55‑gal drums ≈ 44 lb (empty) |
How the hull weight was estimated:
Full‑scale: 60 % of each leg is underwater → submerged volume per leg = 0.6 × 439.8 ft³ = 263.9 ft³. Four legs → 1 055.6 ft³ displaced. Seawater density ≈ 64 lb/ft³ → buoyant force ≈ 67 600 lb.
Model (with 5‑in‑diam., 43.75‑in‑long legs):
This buoyancy is more than enough to support the model body (~44 lb), giving a stable floating platform.
| Component | Full‑Scale (in / lb) | Model (in / lb) | Notes |
|---|---|---|---|
| Leg diameter | 48 in (4 ft) | 5 in (given) | Scale 9.6:1 |
| Leg length | 420 in (35 ft) | 43.75 in (≈ 44 in) | — |
| Leg weight (steel) | ≈ 215 600 lb each | ≈ 244 lb each (if steel) | Model will likely use lightweight material |
| Body length | 720 in (60 ft) | 67 in (two barrels) | ≈ 53.6 ft when scaled up |
| Body width/dia. | 168 in (14 ft) | 22.5 in (one barrel) | ≈ 18 ft when scaled up |
| Body weight (hull) | ≈ 58 500 lb (steel) | ≈ 44 lb (two plastic drums) | Model uses empty drums |
| Buoyancy (legs) | ≈ 67 600 lb | ≈ 76 lb | Sufficient for model |
Enjoy building your scale seastead! If you need further details (e.g., cable tensions, motion tests, or a CAD sketch), just let me know.
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