Below is a complete, self‑contained HTML page that summarises the route, the speed model, a segment‑by‑segment breakdown and the resulting travel‑time estimate. You can save this code as an `.html` file (e.g., `seastead_circumnavigation.html`) and open it in any browser or embed it in a site. ```html
This page provides a rough engineering estimate of how long it would take a solar‑ and kite‑propelled seastead to circle the globe while staying mostly in “low‑risk” latitudes (avoiding the Roaring Forties & Furious Fifties) and avoiding tropical cyclones.
Because the kite is the fastest, we will run it whenever the wind direction permits. Typical ocean‑wind statistics suggest we can expect kite‑friendly conditions for roughly 8 – 10 h per day in the trade‑wind belts and 6 – 8 h per day in the mid‑latitude westerlies.
In less favorable wind regimes (e.g., the South Atlantic) the kite may be usable only ~5 h/day, which lowers the average to ~1.8 mph; in the best sections (North Atlantic Gulf Stream) it can be ~2.5 mph. The range of 1.8 – 2.5 mph gives a realistic envelope for the estimate.
The route stays north of ≈ 35° S except for a short stretch around Cape Agulhas, keeping wave heights generally under 15 ft. The main way‑points are:
Figure – Approximate low‑latitude circumnavigation (west‑about). The dashed line is schematic; real routing would follow weather‑forecast adjustments.
| Segment | Approx. Distance (mi) | Assumed Avg. Speed (mph) | Time (days) |
|---|---|---|---|
| Pacific (Hawaii → Philippines) | 9,500 | 2.3 | 172 |
| Indonesian Through‑flow & Indian Ocean (Philippines → Cape Agulhas) | 7,800 | 2.2 | 147 |
| South Atlantic (Cape Agulhas → Caribbean) | 5,200 | 1.9 | 114 |
| North Atlantic / Gulf Stream (Caribbean → Azores) | 3,800 | 2.5 | 63 |
| Return to Hawaii (via Panama) | 4,200 | 2.1 | 83 |
| Total | 30,500 | – | ≈ 579 |
Distances are rounded and include modest detours to stay clear of the Roaring Forties/Furious Fifties. The actual path length around the globe at low latitudes is ≈ 25 – 26 k mi; the extra ~4 k mi comes from detours (e.g., Indonesian archipelago, Panama Canal).
Total assumed delay ≈ 28 days (≈ 1 month). Adding this to the pure sailing time gives:
| Kite‑hours per day | Avg. speed (mph) | Sailing days (no delays) | Total calendar days (incl. 28‑day weather buffer) |
|---|---|---|---|
| 6 h | 1.8 | ≈ 680 | ≈ 708 days (≈ 1.9 yr) |
| 8 h (base case) | 2.1 | ≈ 579 | ≈ 607 days (≈ 1.66 yr) |
| 10 h | 2.4 | ≈ 506 | ≈ 534 days (≈ 1.46 yr) |
Thus, depending on how often the wind aligns with our heading, the circumnavigation would likely take between 1.4 and 1.9 years.
These numbers are engineering‑order‑of‑magnitude estimates. Real‑world performance will vary with seasonal weather patterns, exact wind‑angle windows, and the exact current‑assist encountered each day.
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