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Seastead Scale Model & Full Scale Analysis
🌊 Seastead Wing-Float/Leg: Scale Model & Full-Scale Analysis
Part 1: Mold Geometry & Foam Volume
Mold Description
The mold approximates a wing/airfoil cross-section:
- Leading edge: Half of a 4″ PVC pipe, 3.5 ft long. Measured inside span: 3.75″
- Trailing sides: Two plywood pieces, each 3.5 ft × 16″, attached via hinges to the pipe edges
- A trash bag liner keeps foam from sticking
CROSS-SECTION VIEW (not to scale)
Leading edge
(half-pipe, ~4" OD)
___----___
/ \
/ \ ← inside span ~3.75"
| |
\ /
\ Plywood / Plywood
\ (16" each) / (16" each)
\ /
\ /
\ /
\ /
\ /
\ /
\ /
Trailing edge
Cross-Section Area Calculation
We need to compute the area of the wing cross-section, which consists of:
- A semicircular leading edge (interior of the half-pipe)
- Two flat plywood sides extending back to a trailing point
Leading edge semicircle:
PVC pipe OD = 4.0 inches
PVC pipe wall thickness (standard Schedule 40) ≈ 0.237 inches
PVC pipe ID = 4.0 - 2×0.237 = 3.526 inches
However, measured inside span = 3.75 inches.
This suggests the pipe is closer to a thin-wall pipe or the
measurement is across the inside of the cut half.
For a 4" OD pipe cut in half, the inside chord would be
close to the ID. The measured 3.75" makes sense for a
thin-wall (SDR/DWV) 4" PVC pipe:
→ Wall thickness ≈ 0.125" (thin wall)
→ ID ≈ 3.75"
Inside radius of half-pipe: r = 3.75 / 2 = 1.875 inches
Semicircle area:
A_semi = ½ × π × r²
A_semi = ½ × π × (1.875)²
A_semi = ½ × π × 3.5156
A_semi = 5.522 in²
Triangular portion from plywood sides:
Each plywood piece is 16″ long and hinges from an edge of the half-pipe. The two pieces meet at a trailing point forming a triangle. The base of this triangle equals the inside span of the pipe (3.75″) and the height is 16″.
A_triangle = ½ × base × height
A_triangle = ½ × 3.75 × 16
A_triangle = 30.0 in²
⚠️ Note on geometry: The 16" plywood pieces likely don't extend perfectly
perpendicular to the span. They angle inward from the pipe edges to meet at a trailing
point. The triangle base = 3.75" (pipe span) and height ≈ 16" (plywood length ≈
hypotenuse, so actual height ≈ √(16² − 1.875²) ≈ 15.89"). The difference is negligible,
so we use 16" as the effective height.
Total cross-section area:
A_total = A_semi + A_triangle
A_total = 5.522 + 30.0
A_total = 35.52 in²
Volume of the mold:
Length = 3.5 ft = 42 inches
V = A_total × Length
V = 35.52 in² × 42 in
V = 1,491.9 in³
Convert to more useful units:
1 gallon = 231 in³
V = 1,491.9 / 231 = 6.45 gallons
1 US cup = 14.4375 in³
V = 1,491.9 / 14.4375 = 103.3 cups
In cubic feet: V = 1,491.9 / 1728 = 0.8634 ft³
In liters: V = 1,491.9 × 0.016387 = 24.45 liters
📐 Mold Volume ≈ 1,492 in³ ≈ 0.863 ft³ ≈ 6.45 gallons ≈ 24.5 liters
2-Part 2 lb/ft³ Foam Requirements
Two-part polyurethane pour foam (2 lb density) is mixed at a 1:1 ratio by volume (Part A : Part B). The liquid expands to fill the mold. The expansion ratio depends on the target density:
Target foam density = 2.0 lb/ft³
Mixed liquid density (typical) ≈ 68–72 lb/ft³ (≈ 9 lb/gal)
Approximate expansion ratio = ~35:1
Volume of mixed liquid needed:
V_liquid = V_mold / expansion_ratio
V_liquid = 1,492 in³ / 35 = 42.6 in³
In cups: 42.6 / 14.4375 = 2.95 cups of mixed liquid
Each part (A and B) at 1:1 ratio:
Part A = 1.48 cups ≈ 1.5 cups
Part B = 1.48 cups ≈ 1.5 cups
⚠️ Practical Advice:
- Manufacturers typically specify the expansion ratio on the product. Common 2 lb/ft³ foams expand ~25× to 35× (free rise). Check your specific product's data sheet.
- In a closed or constrained mold, you should overfill by 10–25% to ensure complete filling and proper density. The foam will be slightly denser than free-rise spec.
- Pour in a warm environment (70–80°F) for best results.
- With a trash-bag liner in an open-top-ish mold, the foam may free-rise out the back — consider clamping the plywood at a set angle and sealing the trailing edge.
🧪 Mix approximately 1.5 cups Part A + 1.5 cups Part B (3 cups total mixed liquid)
For safety margin in a constrained mold: ~1.75 cups each (3.5 cups total)
Verify with your foam product's stated expansion ratio. At 25× expansion you'd need ~2.1 cups each.
Weight of one foam float
Volume = 0.863 ft³
Density = 2.0 lb/ft³
Weight = 0.863 × 2.0 = 1.73 lbs per float
Part 2: Model Buoyancy & Maximum Total Weight
If 3 wing/legs are each 50% submerged in seawater, we need to find the buoyancy force.
Seawater density = 64.0 lb/ft³ (approximately)
Volume of one float = 0.863 ft³
Submerged volume (50%) = 0.863 × 0.50 = 0.4317 ft³
Buoyancy per float = ρ_sw × V_submerged
Buoyancy per float = 64.0 × 0.4317 = 27.63 lbs
Total buoyancy (3 floats) = 3 × 27.63 = 82.9 lbs
For the model to float at 50% submersion, the total weight must equal the total buoyancy:
Total model weight = Total buoyancy force
Total model weight = 82.9 lbs
Weight of 3 foam floats = 3 × 1.73 = 5.19 lbs
Remaining for structure/payload = 82.9 − 5.19 = 77.7 lbs
⚖️ Total model weight for 50% submersion on 3 floats ≈ 82.9 lbs
(Foam floats weigh ~5.2 lbs total, leaving ~77.7 lbs for the platform structure, tensegrity elements, and payload)
⚠️ Note: With 2 lb/ft³ foam, these floats are very light relative to the displaced water.
The tensegrity platform structure above will need to be substantial (or ballasted) to bring total weight
to ~83 lbs for proper 50% draft simulation. This is actually a nice design feature — you have huge
reserve buoyancy for the model.
Part 3: Froude Scaling — Full-Scale Dimensions (1:6 Scale)
With a scale factor λ = 6, all linear dimensions scale by 6×:
| Dimension |
Model (1:6) |
Full Scale (×6) |
| Float length |
3.5 ft (42 in) |
21 ft (252 in) |
| Leading edge diameter (inside) |
3.75 in |
22.5 in (1.875 ft) |
| Chord (nose to tail) |
~17.875 in (1.49 ft) |
107.25 in (8.94 ft) |
| Max thickness (at leading edge) |
3.75 in |
22.5 in (1.875 ft) |
| Plywood/side panel length |
16 in |
96 in (8 ft) |
Froude Scaling Relationships
| Quantity |
Scaling Factor |
Value for λ=6 |
| Length |
λ |
6 |
| Area |
λ² |
36 |
| Volume |
λ³ |
216 |
| Mass / Force |
λ³ (same fluid) |
216 |
| Velocity |
√λ |
2.449 |
| Time |
√λ |
2.449 |
| Power |
λ3.5 |
529.1 |
📏 Full-scale float: 21 ft long × ~9 ft chord × ~1.9 ft max thickness
Cross-section area: 35.52 in² × 36 = 1,279 in² = 8.88 ft²
Volume per float: 0.863 ft³ × 216 = 186.5 ft³ per float
Part 4: Full-Scale Displaced Seawater (50% Submersion)
Method 1: Direct Calculation
Full-scale volume per float = 186.5 ft³
Submerged volume (50%) = 93.24 ft³
Seawater density = 64.0 lb/ft³
Displaced mass per float = 64.0 × 93.24 = 5,967 lbs
≈ 5,967 lbs (2.98 US tons)
For 3 floats:
Total displaced mass = 3 × 5,967 = 17,902 lbs
≈ 17,900 lbs (8.95 US tons)
Method 2: Froude Scaling from Model
Model buoyancy per float = 27.63 lbs
Full-scale buoyancy = 27.63 × λ³ = 27.63 × 216 = 5,968 lbs ✓ (consistent)
🌊 Displaced seawater per float (50% submerged) ≈ 5,967 lbs (2.98 tons)
🌊 Total for 3 floats ≈ 17,900 lbs (8.95 tons)
This means the full-scale seastead platform could weigh up to ~17,900 lbs (structure + payload) and float at 50% draft.
Part 5: Drag Forces at Full Scale (1, 2, 3 MPH)
Setup & Assumptions
The floats are oriented with the leading edge forward (low Cd direction), moving through seawater. The submerged cross-section (50% of each float) presents a certain frontal area and wetted surface to the flow.
Drag Components
For a submerged streamlined body at low speeds, we consider:
- Form (pressure) drag — from the cross-sectional shape
- Skin friction drag — from the wetted surface area
- Wave-making drag — at these very low Froude numbers, this is minimal
Geometry of Submerged Portion
Full-scale float:
Length (span, vertical when installed) = 21 ft
Submerged length = 10.5 ft (50%)
Chord = 8.94 ft (nose to tail, direction of travel)
Max thickness = 1.875 ft (at leading edge)
The float moves horizontally, chord-wise through the water.
Frontal area per float (submerged portion, viewed from flow direction):
A_frontal = submerged_length × max_thickness
A_frontal = 10.5 ft × 1.875 ft = 19.69 ft²
Wetted surface area per float (submerged):
Approximate perimeter of cross-section:
Semicircle arc = π × r = π × 0.9375 = 2.945 ft
Two side panels = 2 × 8 ft = 16 ft (full scale)
Total perimeter ≈ 18.95 ft
Wetted surface = perimeter × submerged_length
S_wet = 18.95 × 10.5 = 199.0 ft² per float
Thickness-to-chord ratio: t/c = 1.875 / 8.94 = 0.210
This is a relatively thick "airfoil" (~21% t/c), similar to
a NACA 0021. For a well-faired shape at low Reynolds numbers,
a reasonable total drag coefficient based on frontal area:
C_d (frontal) ≈ 0.08 to 0.12 for a streamlined strut/foil shape
(much less than a cylinder at ~1.0, much more than a thin foil)
We'll use C_d = 0.10 (based on frontal area) as a reasonable
estimate for this blunt-leading-edge shape. This accounts for
both form drag and skin friction.
Drag Force Calculation
Drag equation: Fd = ½ × ρ × V² × Cd × A
Seawater density: ρ = 1.99 slugs/ft³ (= 64 lb/ft³ ÷ 32.174 ft/s²)
Speed conversions:
1 MPH = 1.467 ft/s
2 MPH = 2.933 ft/s
3 MPH = 4.400 ft/s
Frontal area per float (submerged) = 19.69 ft²
C_d = 0.10
Number of floats = 3
Total frontal area = 3 × 19.69 = 59.06 ft²
| Speed (MPH) |
Speed (ft/s) |
½ρV² (psf) |
Drag per Float (lbs) |
Total Drag, 3 Floats (lbs) |
| 1 |
1.467 |
2.14 |
4.2 |
12.6 |
| 2 |
2.933 |
8.56 |
16.9 |
50.5 |
| 3 |
4.400 |
19.27 |
37.9 |
113.8 |
Sample calculation for 1 MPH:
q = ½ × 1.99 × (1.467)² = ½ × 1.99 × 2.152 = 2.141 lb/ft²
F_per_float = 2.141 × 0.10 × 19.69 = 4.22 lbs
F_total = 3 × 4.22 = 12.6 lbs
🚢 Total drag force (3 floats, oriented streamlined):
@ 1 MPH: ~13 lbs
@ 2 MPH: ~51 lbs
@ 3 MPH: ~114 lbs
Drag scales with velocity squared. These are low speeds — the Froude number
Fr = V/√(gL) ranges from 0.05 to 0.15, so wave-making resistance is minimal.
⚠️ Additional drag sources not included above:
- Tensegrity cables/structure between floats and platform
- The platform itself (if it's close to the water surface)
- Waterline intersection / free-surface effects
- Marine growth / surface roughness over time
- Appendage drag (sensors, ladders, etc.)
A practical design factor of 1.5× to 2× on these bare-hull numbers is prudent.
Part 6: Motor & Propeller Power Requirements
Assumptions
- Electric motor efficiency: ηmotor = 85% (typical brushless DC marine motor)
- Propeller efficiency: ηprop = 45% (conservative for low-speed, displacement-type vessel with likely undersized props)
- Drive train / controller losses: ηdrive = 92% (ESC, wiring, etc.)
- Overall propulsive efficiency: ηtotal = 0.85 × 0.45 × 0.92 = 0.352 (~35%)
On propeller efficiency: At these very low speeds (1–3 MPH) for a ~9-ton vessel,
you're in a regime where propeller design matters enormously. A well-matched large-diameter,
slow-turning prop could achieve 50–55% efficiency. A poorly matched small prop might only
manage 30–35%. We'll show both a conservative and optimistic case.
Power Calculations
Effective (towing) power: Pe = Fdrag × V
Shaft power: Pshaft = Pe / ηprop
Electrical input power: Pelec = Pshaft / (ηmotor × ηdrive)
1 HP = 550 ft·lbs/s = 745.7 watts
Conservative Case (ηtotal = 35%)
| Speed (MPH) |
Total Drag (lbs) |
Effective Power (watts) |
Electrical Input (watts) |
Electrical Input (HP) |
| 1 |
12.6 |
25 |
72 |
0.10 |
| 2 |
50.5 |
201 |
573 |
0.77 |
| 3 |
113.8 |
680 |
1,935 |
2.60 |
Sample calculation for 2 MPH (conservative):
P_effective = 50.5 lbs × 2.933 ft/s = 148.1 ft·lbs/s = 200.9 watts
P_electrical = 200.9 / 0.352 = 570.7 watts
Optimistic Case (ηtotal = 48% — well-designed large prop system)
| Speed (MPH) |
Total Drag (lbs) |
Effective Power (watts) |
Electrical Input (watts) |
Electrical Input (HP) |
| 1 |
12.6 |
25 |
53 |
0.07 |
| 2 |
50.5 |
201 |
419 |
0.56 |
| 3 |
113.8 |
680 |
1,416 |
1.90 |
⚡
Electrical power for 3 full-scale wing-floats at various speeds:
| Speed |
Conservative (watts) |
Optimistic (watts) |
Practical Estimate (watts) |
| 1 MPH |
72 W |
53 W |
~60–75 W |
| 2 MPH |
573 W |
419 W |
~420–575 W |
| 3 MPH |
1,935 W |
1,416 W |
~1,400–1,950 W |
Power scales with V³ — doubling speed requires 8× the power!
Practical Motor Recommendations (Full Scale)
| Target Speed |
Suggested Motor Size |
Battery Considerations (for 8 hours) |
| 1 MPH (station-keeping) |
Single trolling motor, ~100W |
~600 Wh = modest 12V battery |
| 2 MPH (repositioning) |
1–2 trolling motors or small pod drive, ~750W total |
~4.6 kWh = small solar + battery bank |
| 3 MPH (transit) |
2–3 kW electric outboard or pod drive |
~15.5 kWh = substantial battery bank |
💡 Design Insight: At just 1 MPH, a single ~100W solar panel could potentially
provide continuous station-keeping power during daylight hours. This is very favorable for a
seastead that primarily needs to hold position with occasional repositioning. A 1 kW solar
array could sustain ~2 MPH cruising during peak sun.
Summary of All Results
| Model Scale (1:6) |
| Float volume | 1,492 in³ (0.86 ft³, 6.45 gal) |
| Foam per float (2 lb/ft³) | ~1.73 lbs |
| Foam mix: Part A + Part B | ~1.5 + 1.5 cups (add 15-25% margin) |
| Buoyancy per float (50% submerged) | 27.6 lbs |
| Total model weight (3 floats, 50% draft) | 82.9 lbs |
| Full Scale (×6) |
| Float dimensions | 21 ft long × 8.9 ft chord × 1.9 ft thick |
| Float volume | 186.5 ft³ per float |
| Displaced seawater per float (50%) | 5,967 lbs |
| Total displacement (3 floats) | 17,900 lbs (8.95 tons) |
| Drag @ 1 MPH (3 floats) | ~13 lbs → 60–75 W electrical |
| Drag @ 2 MPH (3 floats) | ~51 lbs → 420–575 W electrical |
| Drag @ 3 MPH (3 floats) | ~114 lbs → 1,400–1,950 W electrical |
Analysis prepared for seastead design evaluation.
All calculations use standard naval architecture methods and reasonable engineering assumptions.
Values should be validated with physical model testing and CFD analysis for final design.
Key References: Principles of Naval Architecture (SNAME),
Froude scaling laws, ITTC recommended procedures for model testing.
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